Optimal. Leaf size=58 \[ -\frac {\cot ^6(a+b x)}{6 b}+\frac {\cot ^4(a+b x)}{4 b}-\frac {\cot ^2(a+b x)}{2 b}-\frac {\log (\sin (a+b x))}{b} \]
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Rubi [A] time = 0.03, antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3473, 3475} \[ -\frac {\cot ^6(a+b x)}{6 b}+\frac {\cot ^4(a+b x)}{4 b}-\frac {\cot ^2(a+b x)}{2 b}-\frac {\log (\sin (a+b x))}{b} \]
Antiderivative was successfully verified.
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Rule 3473
Rule 3475
Rubi steps
\begin {align*} \int \cot ^7(a+b x) \, dx &=-\frac {\cot ^6(a+b x)}{6 b}-\int \cot ^5(a+b x) \, dx\\ &=\frac {\cot ^4(a+b x)}{4 b}-\frac {\cot ^6(a+b x)}{6 b}+\int \cot ^3(a+b x) \, dx\\ &=-\frac {\cot ^2(a+b x)}{2 b}+\frac {\cot ^4(a+b x)}{4 b}-\frac {\cot ^6(a+b x)}{6 b}-\int \cot (a+b x) \, dx\\ &=-\frac {\cot ^2(a+b x)}{2 b}+\frac {\cot ^4(a+b x)}{4 b}-\frac {\cot ^6(a+b x)}{6 b}-\frac {\log (\sin (a+b x))}{b}\\ \end {align*}
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Mathematica [A] time = 0.31, size = 56, normalized size = 0.97 \[ -\frac {2 \cot ^6(a+b x)-3 \cot ^4(a+b x)+6 \cot ^2(a+b x)+12 \log (\tan (a+b x))+12 \log (\cos (a+b x))}{12 b} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.50, size = 126, normalized size = 2.17 \[ \frac {18 \, \cos \left (2 \, b x + 2 \, a\right )^{2} - 3 \, {\left (\cos \left (2 \, b x + 2 \, a\right )^{3} - 3 \, \cos \left (2 \, b x + 2 \, a\right )^{2} + 3 \, \cos \left (2 \, b x + 2 \, a\right ) - 1\right )} \log \left (-\frac {1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) + \frac {1}{2}\right ) - 18 \, \cos \left (2 \, b x + 2 \, a\right ) + 8}{6 \, {\left (b \cos \left (2 \, b x + 2 \, a\right )^{3} - 3 \, b \cos \left (2 \, b x + 2 \, a\right )^{2} + 3 \, b \cos \left (2 \, b x + 2 \, a\right ) - b\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.44, size = 208, normalized size = 3.59 \[ \frac {\frac {{\left (\frac {12 \, {\left (\cos \left (b x + a\right ) - 1\right )}}{\cos \left (b x + a\right ) + 1} + \frac {87 \, {\left (\cos \left (b x + a\right ) - 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{2}} + \frac {352 \, {\left (\cos \left (b x + a\right ) - 1\right )}^{3}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{3}} + 1\right )} {\left (\cos \left (b x + a\right ) + 1\right )}^{3}}{{\left (\cos \left (b x + a\right ) - 1\right )}^{3}} + \frac {87 \, {\left (\cos \left (b x + a\right ) - 1\right )}}{\cos \left (b x + a\right ) + 1} + \frac {12 \, {\left (\cos \left (b x + a\right ) - 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{2}} + \frac {{\left (\cos \left (b x + a\right ) - 1\right )}^{3}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{3}} - 192 \, \log \left (\frac {{\left | -\cos \left (b x + a\right ) + 1 \right |}}{{\left | \cos \left (b x + a\right ) + 1 \right |}}\right ) + 384 \, \log \left ({\left | -\frac {\cos \left (b x + a\right ) - 1}{\cos \left (b x + a\right ) + 1} + 1 \right |}\right )}{384 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.03, size = 57, normalized size = 0.98 \[ -\frac {\cot ^{6}\left (b x +a \right )}{6 b}+\frac {\cot ^{4}\left (b x +a \right )}{4 b}-\frac {\cot ^{2}\left (b x +a \right )}{2 b}+\frac {\ln \left (\cot ^{2}\left (b x +a \right )+1\right )}{2 b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.40, size = 48, normalized size = 0.83 \[ -\frac {\frac {18 \, \sin \left (b x + a\right )^{4} - 9 \, \sin \left (b x + a\right )^{2} + 2}{\sin \left (b x + a\right )^{6}} + 6 \, \log \left (\sin \left (b x + a\right )^{2}\right )}{12 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 7.46, size = 340, normalized size = 5.86 \[ x\,1{}\mathrm {i}-\frac {\ln \left ({\mathrm {e}}^{a\,2{}\mathrm {i}}\,{\mathrm {e}}^{b\,x\,2{}\mathrm {i}}-1\right )}{b}+\frac {32}{b\,\left (5\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}-10\,{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}+10\,{\mathrm {e}}^{a\,6{}\mathrm {i}+b\,x\,6{}\mathrm {i}}-5\,{\mathrm {e}}^{a\,8{}\mathrm {i}+b\,x\,8{}\mathrm {i}}+{\mathrm {e}}^{a\,10{}\mathrm {i}+b\,x\,10{}\mathrm {i}}-1\right )}+\frac {32}{3\,b\,\left (1+15\,{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}-20\,{\mathrm {e}}^{a\,6{}\mathrm {i}+b\,x\,6{}\mathrm {i}}+15\,{\mathrm {e}}^{a\,8{}\mathrm {i}+b\,x\,8{}\mathrm {i}}-6\,{\mathrm {e}}^{a\,10{}\mathrm {i}+b\,x\,10{}\mathrm {i}}+{\mathrm {e}}^{a\,12{}\mathrm {i}+b\,x\,12{}\mathrm {i}}-6\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\right )}+\frac {6}{b\,\left ({\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}-1\right )}+\frac {18}{b\,\left (1+{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}-2\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\right )}+\frac {104}{3\,b\,\left (3\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}-3\,{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}+{\mathrm {e}}^{a\,6{}\mathrm {i}+b\,x\,6{}\mathrm {i}}-1\right )}+\frac {44}{b\,\left (1+6\,{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}-4\,{\mathrm {e}}^{a\,6{}\mathrm {i}+b\,x\,6{}\mathrm {i}}+{\mathrm {e}}^{a\,8{}\mathrm {i}+b\,x\,8{}\mathrm {i}}-4\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.22, size = 85, normalized size = 1.47 \[ \begin {cases} \tilde {\infty } x & \text {for}\: \left (a = 0 \vee a = - b x\right ) \wedge \left (a = - b x \vee b = 0\right ) \\x \cot ^{7}{\relax (a )} & \text {for}\: b = 0 \\\frac {\log {\left (\tan ^{2}{\left (a + b x \right )} + 1 \right )}}{2 b} - \frac {\log {\left (\tan {\left (a + b x \right )} \right )}}{b} - \frac {1}{2 b \tan ^{2}{\left (a + b x \right )}} + \frac {1}{4 b \tan ^{4}{\left (a + b x \right )}} - \frac {1}{6 b \tan ^{6}{\left (a + b x \right )}} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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